Sobre richbarna
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Comentarios 35 Más comentarios
  • es que lo vamos a reventar todo,allez paris! hace 11 años en Sochaux - PSG
  • es que lo vamos a recentar todo,allez paris! hace 11 años en Sochaux - PSG
  • pues toma! somos lideres y mañana pierde el montpellier,jajaja hace 11 años en Stade Rennais - Montpellier
  • ya esta bien,esta noche arrasamos 1-3 hace 11 años en Valenciennes - PSG
  • de momento vamos ganando y jugando muy bien,allez paris! hace 12 años en Auxerre - PSG
  • 1-2 hace 12 años en Nancy - PSG
  • 4-1 para el psg hace 12 años en PSG - Girondins Bordeaux
  • 0-2 para Paris!! hace 12 años en Caen - PSG
  • 0-2 para mi PSG! hace 12 años en Stade Brestois - PSG
  • que desilusion perder contra un equipillo de la ligue 1,menos mal que existe el mercato de invierno!! hay que fichar nuevos jugadores,el dinero ya no es un problema por el club oleeeeeeeeeeeee! hace 12 años en PSG - Nancy

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Estadísticas de richbarna
  • Comentarios creados: 35
  • Votos a favor: 3
  • Fotos subidas: 0
  • Videos subidos: 0
  • Usuario desde: 13 Ago 11 16:24
  • Último login: 17 Feb 13 16:58

  USO DE MEMORIA  
4,019,848 bytes
  BENCHMARKS  
Loading Time Base Classes  0.0016
Controller Execution Time ( Uprofile / Index )  0.0955
Total Execution Time  0.0971
  CADENA URL  
/usuario/richbarna
  GET DATOS  
$_GET['/usuario/richbarna']  
  POST DATOS  
No hay datos POST existentes
  CONSULTAS (31)  
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0.0019  SELECT dt.nameShow, dt.basealias, t.name FROM `teams` as t INNER JOIN `datateams` as dt ON dt.id = t.teamId WHERE league_id = 1327
0.0018  SELECT id, year FROM leagues WHERE id IN (1910,1910,1327,1327,1327,1327,1327,1327,1327,1327)
0.0019   SELECT c.id, c.league_id, dt1.nameShow AS team1_name, dt2.nameShow AS team2_name, dt1.basealias AS basealias1, dt2.basealias AS basealias2, c.extra FROM calendars2013 AS c INNER JOIN datateams AS dt1 ON c.datateam1=dt1.id INNER JOIN datateams AS dt2 ON c.datateam2=dt2.id WHERE c.id IN (1017)
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0.0018  SELECT COUNT(DISTINCT `id`) AS num_total FROM videos WHERE `author_id` = 193261
0.0018  SELECT COUNT(DISTINCT `id`) AS num_total FROM pictures WHERE `author_id` = 193261